Question

A black body radiates 5000 joules of energy per second at 227°c temperature.What will be the rate of radiation of energy at 727 °c temperature?

Answer 1

Answer:

P=sigma*area*temp^4

T1=273+227=500

T2=273+727=1000

5000=sigma*area*500^4

x=sigma*area*1000^4

solve for x:

x=5000*2^4

Explanation:

Answer 2

Explanation:

5000 joules of energy per sec at 227 degree Celsius.

so at 1 degree Celsius it radiate =5000/227

=22.026....

727×22.026.....

=16013.215... energy will radiate.

hope it will help you.