A blacksmith bent a steel wire in the form of a square enclose an area of 121 sq.cm.If the same wire he bent in the form of a circle,then the area of the circle is
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Ist case :
Area of square =121 sq.cm
Side of square = √121 =11cm
llnd case :
Perimeter of square =4×11 =44cm
Perimeter of square = Circumference of circle
lllrd case :
Circumference of circle =2pie r
44 = 2 ×22/7 ×r
r=44×7/44
r=7cm
lVth case :
Area of circle =pie r^2 =22/7 ×7 ×7 =22×7 =154cm^2
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Area of square =121 sq.cm
Side of square = √121 =11cm
llnd case :
Perimeter of square =4×11 =44cm
Perimeter of square = Circumference of circle
lllrd case :
Circumference of circle =2pie r
44 = 2 ×22/7 ×r
r=44×7/44
r=7cm
lVth case :
Area of circle =pie r^2 =22/7 ×7 ×7 =22×7 =154cm^2
HOPE IT WILL HELP U...
PLZ MARK IT AS BRAINLIEST ANSWER..
Khushi020:
plz mark it as brainliest answer..
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let the side of square be x centimetre
area of square=x^2=121 sq.cm
x=_/121 cm
x=11cm
perimeter of the square=4×11=44cm
As the wire is bent in the form of a circle,
circumference of the circle=perimeter of the square
circumference=2pi r
=r=44/2pi m=44×7/2×22 cm=7cm
area of circle=pi r^2
=22/7×7^2=22/7×49=22×7=154 square centimetre.
area of square=x^2=121 sq.cm
x=_/121 cm
x=11cm
perimeter of the square=4×11=44cm
As the wire is bent in the form of a circle,
circumference of the circle=perimeter of the square
circumference=2pi r
=r=44/2pi m=44×7/2×22 cm=7cm
area of circle=pi r^2
=22/7×7^2=22/7×49=22×7=154 square centimetre.
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