Question

A blacksmith fixes iron ring on the wooden wheel of a bullock cart. The diameter of the rim the iron ring are 5.243m 5.231m respectively at 27 o C. To what temperature should the ring be heated so as to fit the rim of the wheel?

Answer 1

Given  

T1 = 27° C 
LT1 = 5.231 m 

LT2 = 5.243 m 

So,  
LT2 = LT1 [1 + al (T2-T1) ] 

5.243m = 5.231m [ 1+1.20 x10-5 K-1 (T2 - 27°C) 

Or T2 = 218°C

Answer 2

Answer:

Explanation:

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