a bloack of mass under root 3kg is resting on a horizontal plane (coefficient of static friction =1/2under root3 ) . a foce is applied to the block at an angle of 60 . the minimum magnitude of force for which the block begins to slide is
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Hello. ☺
That's an easy question of NLM .
=> Frictional Force = Fcos60 (begins slide)
u.n= F* ½
1/2root3*(mg+F sin60) = F*1/2
F/4 + 5 = F*1/2
Hence
→ F= 20 N
That's an easy question of NLM .
=> Frictional Force = Fcos60 (begins slide)
u.n= F* ½
1/2root3*(mg+F sin60) = F*1/2
F/4 + 5 = F*1/2
Hence
→ F= 20 N
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