A block 100mm x 100mm base and 10mm height. What will the direct shear stress in the element when a tangential force of 10kN is applied to the upper edge to a displacement 1mm relative to lower face? Answer in SI units.
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Step-by-step explanation:
In ΔABC tanr= 101
For small angles tanr=r
∴ Shear strain r= 101 =0.1
Shear stress=
Area on which force is applied
Force applied= 100×100mm
210×10 3
=1N/mm 2 =1MP a
∴ Stress(Shear)=1MPa
Strain(Shear)=0.1.
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