Question

A block A of mass 2 kg starts slipping down the inclined plane of inclination 37° from a point 4.8 m
away from the spring of constant k= 1000 N/m. The coefficient of kinetic friction between the block
and the inclined plane is 0.5. If the maximum compression in the spring is x
max, then find the value of
10x, in ​

Answer 1

Answer:

Topic :-

Mechanics

Given :-

A block A of mass 2 kg starts slipping down the inclined plane of inclination 37° from a point 4.8 m away from the spring of constant k = 1000 N/m. The coefficient of kinetic friction between the block and the inclined plane is 0.5.

Formula to be Used :-

x is maximum compression in spring.

Frictional force when a block slips down =

Force with which block slips down =

Solution :-

It is given that,

Mass of block, m = 2 kg

Inclination of plane = 37°

Distance traversed by block = Distance between block and spring + Maximum Compression in spring

Distance traversed by block = ( 4.8 + x ) metres

Spring Constant, k = 1000 N/m

Kinetic friction between block and plane = 0.5

Now, calculate work done by block,

Work done = Force × Displacement

As we know, for maximum compression whole energy of block will shift into spring energy. So, we will equate both equations.

So,

Apply, quadratic formula,

x can't be negative so we reject negative value of 'x'.

So,

Answer :-

So, ten times of maximum compression in spring is 2 metres.

Explanation:

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