A block a of mass 5 kg is placed on a rough table the coefficient of Static and kinetic friction between surfaces of clock and table is 0.4 and 0.3 respectively if force is exerted on the block is 10 Newton the force of friction between the block and the table is
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Static friction = kmg
= 0.4×5×10
=20N
As force applied is lower than static friction so body wont move.
The friction between block and table is 10N
= 0.4×5×10
=20N
As force applied is lower than static friction so body wont move.
The friction between block and table is 10N
Answered by
0
Static friction = kmg
= 0.4×5×10
=20N
As force applied is lower than static friction so body wont move.
The friction between block and table is 10N
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