A block a of mass 7kg is placed on a frictionless table, a thread tied to it passes over a frictionless pulley and carries a body b of mass 3 kg at the other end. the acceleration of the system is
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For a body A :
Tension = Mass × acceleration
Let acceleration = a
Tension = ma = 7a
For a body B :
Force = Mass × acceleration
Ma = mg - T
3a = 3 × 10 - 7a
3a + 7a = 30
10a = 30
a = 30/10
a = 3 m/s²
Answered by
1
Answer:
acceleration is 3 m/s²
Explanation:
for body A
t=ma
acceleration=a
t=7a
for body B
f=ma
ma=mg-t
3a=30-7a
10a=30
a=3m/s²
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