. A block A slides over another block B which is placed over a smooth inclined plane as shown in figure. The coefficient of friction between the two blocks A and B is . Mass of block B is two times the mass of block A. The acceleration of the centre of mass of two blocks is
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The acceleration of the center of mass of two blocks is g.sin θ
Explanation:
The force acting on mass A is:
Fa = mgsin θ - T
The force acting on mass B is:
Fb = 2mgsin θ - T
The acceleration at center of mass is given as:
a = (ma (Fa/ma) + mb (Fb/mb))/(ma + mb)
Where,
ma = Mass of block A
mb = Mass of block B
Now, the acceleration is:
a = (3 mg.sin θ)/3m
∴ a = g.sin θ
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