Question

A block A, weighing 100 N, is pulled up a slope of length 5m by means of constant force F( =100 N).

a. What the work done by the force F in moving the block a, 5 m along the slope

b. What is the increase in potential energy of the block A

c. Account for the difference in the work done by the force and the increase in potential energy of the block.​

Answer 1

Explanation:

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Answer 2

Answer: a) - 500J

              b) - 300J

              c) - 200J

Explanation:

A) -> w = f * s

          = 100*5

          = 500J

B) -> u = mgh

        (100 N = 10 KGF)

         = 10 * 10 * 3

         = 300J

C) -> 500 - 300

        200J