Question

A block can slide on a smooth inclined plane of inclination theta kept on the floor of a lift when the lift is descending with the retardation a the acceleration of block relative to incline is

Answer 1

Answer:

The answer is ( g + a) sin θ.

If the mass of the block is m and its acceleration is, say, b.

The lift is descending with a negative acceleration of magnitude a,

a pseudo force is applied downwards on the block.

so, g's effective value becomes $g_{eff}$ = g + a.

So, along the inclined plane, the component for acceleration will be

$g_{eff}$ sin θ = (g + a) sinθ

Explanation:

Answer 2

Here is your answer user.