Question

How do you factor by grouping 4z2+12z−az−3a?

Answer 1

$let \: z \: be \: x \: and \: a \: be \: y. \\ 4x {}^{2} + 12x - yx - 3y \\ = 4x(x + 3) - y(x + 3) \\ = (x + 3)(4x - y) \\ substituiting \: the \: \: original \: values \\ now \\ (x + 3)(4x - y) \\ = (z + 3)(4z - a)$

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