Question

A block has a volume of 210 cm3 and a
hass of 180 g
the block is held just kefore above the surfac
of
a liquid density 0.88 g/cm3
Predict and explain what happens
when the
block is released ?​

Answer 1

According to Archimedes' principle.

Mass of volume displaced is by object is buoyancy force.

Let the volume of wood is V.

then the volume submerged in liquid is V/4

let the density of wood be ρ.

let the density of liquid be ρ

l

=0.8cm

−3

.

weight of wood ρVg.

buoyancy force =

4

ρ

l

V

g

now weight of block is equal to buoyancy force.

ρVg=

4

ρ

l

V

g

So ρ=

4

0.8

=.2gcm

−3

then the volume submerged in oil is 60% of is 3V/5

weight of wood ρVg

buoyancy force =

5

ρ

oil

3V

g

now weight of block is equal to buoyancy force.

ρVg=

5

ρ

oil

3V

g

So ρ

oil

=

3

ρ×5

=

3

0.2×5

=0.33gcm

−3

Answered By=shreyash. .......