Physics, asked by psethi990, 9 months ago

A block is floating in equilibrium with one-fifth of the
block outside the liquid. If the relative density of the
material of the block is 0.9, then the relative density of
the liquid is
0.9
1.0
1.125
0.72

Answers

Answered by shiva0064
7

Answer:

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Answered by knjroopa
4

Explanation:

Given A block is floating in equilibrium with one-fifth of the block outside the liquid. If the relative density of the  material of the block is 0.9, then the relative density of  the liquid is

  • Let the volume of the liquid be 1 litre
  • Relative density of the material of the block is 0.9.
  • Now mass = density x volume
  •                    = 0.9 x 1
  •                   = 0.9
  • The block floats in equilibrium with one-fifth of the block outside.
  • So the 1 – 1/5 = 4/5 inside the liquid.
  • Therefore volume of the liquid displaced will be 4/5
  • Now weight of the object will be equal to the weight of the liquid displaced.
  • So we have mass = relative density x volume of the liquid displaced.
  •                     0.9 = D x 4/5
  •            Or Density D = 0.9 x 5 / 4
  •                Or D = 1.125
  • Therefore relative density of the liquid is 1.125

Reference link will be

https://brainly.in/question/20358153

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