Question

If (1, 3) is the point to which the origin is shifted and the transformed equation is X2

+ Y2

= 1

then the original equation is

1) x2

+ y2

+ 2x + 6y + 8 = 0 2) x2

+ y2

+ 2x + 6y – 8 = 0

3) x2

+ y2

– 2x – 6y + 8 = 0 4) x2

+ y2

– 2x – 6y – 8 = 0​

Answer 1

Answer:

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