how many images would be doemed of an object placed in a room having two of its sides walls and shelling mirror polished
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Your question says that 2 walls are perpendicular (90°)
There is formula for finding number of images=360°/theta-1
Theta=90°
360/90-1=3
For two walls it's 2×3 =6
Also there is ceiling fue to which half images on both walls will be formed when this half images are joined it will form a full image
So total is 3+3+1=7
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