Physics, asked by indupurugeetha, 10 months ago

A block is floating in equilibrium with one-fifth of the
block outside the liquid. If the relative density of the
material of the block is 0.9, then the relative density of
the liquid is
0.9
1.0
1.125
0.72​

Answers

Answered by eshwaripatil
3

Answer:

1.125

Explanation:

let the block have volume 1 ltr or 1000 ml

as the relative density of the block is 0.9

The mass = 0.9× 1000

= 900 gram

It floats in equilibrium with one-fifth of the

block outside the liquid means 4/5 th inside the liquid

volume of the liquid displaced = 4×1000/5

= 800 ml

By rule of floating body

weight of the body = weight of the displaced liquid

900 = relative density × volume of displaced liquid

= relative density × 800

relative density of the liquid = 900 / 800

= 1.125 g/cc

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