A block is kept on a frictionless inclined surface with angle of inclination α. the inclined is given an acceleration v a ro keep the block stationary . then a is equal to [AIEEE 2005]
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Explanation:
In the reference frame of the wedge, pseudo force ma acts towards right and component of this ma is macosα balances the mgsinα.
mgsinα=macosα
⇒a=gtanα
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Explanation:- In the frame of wedge , the force diagram of block is shown in fig ,from free body diagram of wedge
- For block to remain stationary
- macosα = mgsinα
- οr a = gtanα Answer
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