Question

A block is kept on an inclined plane of inclination θ of length l. velocity of particle at the bottom of inclined is (friction coefficent is μ)

Answer 1

1) component of gravitational force =  mgsin(θ)
(2) friction force                                     F = u×R = u×mgcos(θ)
So net force acting on the body will be:
                                                               Fnet = mgsin(θ) − u×mgcos(θ)so acceleration will be as: a = Fnetm = g×[sin(θ)−ucos(θ)]
so the velocity of the block can be calculated using third equation of motion:
Formula:                                            v2 = u2 + 2as v2 = (0)2 + 2×[g×{sin(θ)−ucos(θ)}]×l v = 2gl[sin(θ)−ucos(θ)]

Answer 2

Answer:

i hope this is the correct answer ☺️