Physics, asked by simranstanot7, 7 hours ago

A block is moving with a velocity of 22 m/s. A constant force is applied on the block in the direction opposite to the direction of velocity. After 9 seconds, the velocity is reduced to 13 m/s.​

Answers

Answered by bb1868177
2

Explanation:

u= 22 m/s

v=13m/s

time=9 sec

change in velocity = acceleration v -u /t

13-22/9

a= -1

(- sign is included in the answer as the block is moving in opposite direction)

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