Question

Calculate the number of atoms present in 24g of Helium (He=4u)

Answer 1

Hey!

The answer is:

1 mole of He contains 6.023×10^23 atoms.

1 mole of He = 4 gm of He.

So, 20 gm of He contains — 6.022 X 10^23/4 X 24

= 36.152 X 10^ 23 atoms.

Answer 2

Answer:

36.138×10^23He

Explanation:

1 mole of He contains 6.023×10^23 atoms.

1 mole of He = 4 gm of He.

So, 24 gm of He contains — (24÷4)×6.023×10^23 atoms = 36.138×10^23He atoms.