A block is projected along a rough horizontal road with a speed of 10 m/s. If the coefficient of kinetic friction is 0.10, how far will it travel before coming to rest. Concept of Physics - 1 , HC VERMA , Chapter 6:Friction "
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Solution :
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Due to friction , the body will decelerate.
Let the deceleration be a.
R-mg=0
R=mg----------------(1)
Now, ma-μR=0
ma=μmg
a= μg=0.1 x10=1m/s2
Initial velocity =u=10m/s2
Final velcoity =v=0 m/s
a=-1 m/s2
So from second equation of motion:
S=v²-u²/2a
=0- 10²/2x-1
=100/2
=50m
So it will travel 50m before coming to rest.
***************************************
Due to friction , the body will decelerate.
Let the deceleration be a.
R-mg=0
R=mg----------------(1)
Now, ma-μR=0
ma=μmg
a= μg=0.1 x10=1m/s2
Initial velocity =u=10m/s2
Final velcoity =v=0 m/s
a=-1 m/s2
So from second equation of motion:
S=v²-u²/2a
=0- 10²/2x-1
=100/2
=50m
So it will travel 50m before coming to rest.
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