Question

A block is released from the top of a smooth inclined plane. It reaches the bottom of the plane in 6 s.what is the time taken by the body to cover the first half of the inclined plane?

Answer 1

s = u t + 1/2 a t²

a = g Sin Ф,  where Ф = angle of the inclined plane    

u = 0

Hence, s is directly proportional to t².         If distance is 1/4 th  then time taken will be 1/2.

 So  half of 4 secs  is 2 seconds.

Answer 2

Answer:

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Explanation: