A block is released from the top of a smooth inclined plane. It reaches the bottom of the plane in 6 s.what is the time taken by the body to cover the first half of the inclined plane?
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s = u t + 1/2 a t²
a = g Sin Ф, where Ф = angle of the inclined plane
u = 0
Hence, s is directly proportional to t². If distance is 1/4 th then time taken will be 1/2.
So half of 4 secs is 2 seconds.
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