Question

A block mass 10 kg is placed on a horizontal rough surface of coefficient of friction 0.4. A force of 20 N is applied on it, its acceleration is ​

Answer 1

Given,

mass = 10kg

force = 20N

distance = 0.4

Force = mass × acceleration

20 = 10 × acceleration

20/10 = acceleration

Acceleration = 2m/s²