Question

a block of 10 kg is pulled by a constant speed on a rough horizontal surface by a force of 19.6 n. the coefficient of friction is

Answer 1

HEY
HERE IS YOUR ANSWER
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WE KNOW THAT
FORCE OF FRICTION=COEFFICIENT*NORMAL REACTION
ALSO,
NORMAL REACTION=mg
normal reaction=10*9.8=98
now
19.6=coefficient of friction*98
COEFFICIENT OF FRICTION=0.2
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HOPE IT WILL HELP
PLEASE MARK IT AS BRAINLIEST

Answer 2

Answer:

0.2

Explanation:

10×g=10×9.8=98

19.6/98=0.2 =coefficient of friction mark as brainlist