Question

A block of 4 kg is placed on a plank having mass 8 kg. A force f = 20 n is applied on plank. Then find the friction force betwe

Answer 1

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Incomplete Question

Answer 2

It seems this is what you are looking for:

A block of 4 kg is placed on a plank having a mass of 8 kg. A force f = 20 n is applied on the plank. Then find the friction force between 4 kg and 8 kg block. Here coefficient of friction between 4 kg and 8 kg is u= 0.4, the floor is smooth.

Answer: Friction force will be 20/3 N.

Explanation:

                                ( 4 kg block)

 $U$ = 0.4           ---------------------------------   ( F= 20 N)

                                8 kg plank

•           ma$a$ of ac$n$ of 4kg = $U$g

                       = 4 m/s²

• By this force if there is no sliding

              a= 20/12 = 5/3 < 4

• Therefore, friction force =5/3 x 4

                                                 = 20/3 N

Therefore, the Friction force will be 20/3 N.