Question

a block of a mass 2 kg rests on a roug inclined plain making an angle of 30 degree with horizantal the cofficient of statics friction between the block and the plane is 0.7 the frictional force on the block is

Answer 1

We know that Frictional force F =  u m g cos  θ

                                                     = 0.7 * 2 * 9.8 * cos 30

                                                     = 6.86 * 1.732

                                                    = 11.88N


Hope this helps!