A block of gold and wood have same volume , which experience higher buoyant force?
Answers
A block of gold and would have same volume but wood will experience great buoyant force because the density of gold is greater than that of wood .
The density of gold is higher than wood because it is a metal and hence will sink .
We can verify this by Archimedes principle also.....
......HOPE......
IT HELPS YOU!!!
IF IT DOES HELP YOU..
PLEASE
MARK
AS
BRAINLIEST!!!
^_^
Case 1
If we assume both are denser than water, then they will both experience equal buoyant force. As buoyant force is defined as "equal to the weight of water displace", they will both displace equal water. It's a different thing that the block of gold will be much heavier due to its density, so if will sink to the bottom faster (more downward force)
Case 2
gold sinks, wood doesn't
if the density of wood is less than water, it will float. It will not displace the "water equal to its volume". That is it will displace less water so it will experience less force.
You can try this, take anything that floats place it in water. Push push in inside water, you will feel the object is not pushing at you at all in the beginning (same water level), but as you push it farther (water level rises), it will start pushing you harder. Until it is completely submerged, then force becomes constant (if density is constant, which is a good assumption in your bathroom, NOT sea!). Now if you leave it, it will bounce right back and water will go down.
Since gold sunk, it will experience same force (as case 1, less than wood)