Question

A block of mass 0.5 kg is resting on a smooth horizontal surface. A force of

10N starts acting at 60o

from horizontal. What is the acceleration of the

block ?​

Answer 1

Answer:

acceleration of the block = 10 m/s²

Explanation:

Given that,

A block of mass 0.5 kg is resting on a smooth horizontal surface

force = 10 N at 60° with horizontal

so,

horizontal force = 10 cos60°

= 10 × 1/2

= 5N

given mass = 0.5 kg

acceleration = force/mass

= 5/0.5

= 10 m/s²

so,

acceleration of the block = 10 m/s²

in the horizontal direction

Answer 2

Answer:

acceleration of the block = 10 m/s²

Explanation:

Given that,

A block of mass 0.5 kg is resting on a smooth horizontal surface

and given force

force = 10 N at 60° with horizontal

so,

horizontal force that will act to move the body = 10 cos60°

= 10 × 1/2

= 5N

given mass = 0.5 kg

now,

we have,

force = 5N

mass = 0.5 kg

we know that,

by the second law of motion,

force = mass × acceleration

so,

acceleration = force/mass

putting the values

= 5/0.5

= 10 m/s²

so,

acceleration of the block = 10 m/s²

in the horizontal direction