Question

A block of mass 1 kg is connected with a fixed
wall through a light spring of constant
h = 100 N/m. The surfaces are frictionless,
Initially, spring is in relaxed position. A
horizontal force F of 50 N is applied on the
block. Find the maximum elongation of the
spring​

Answer 1

Answer:

The applied force F must get balanced to the restoring force applied by the spring for maximum elongation.

Hence,

kx = 50

Since, k = 100 N/m

Therefore,

maximum elongation (x) = 0.5 metres.

Hope this helps you !

Answer 2

Answer:

x=1m

Explanation:

m=1kg

spring constant k= 100 N/m

F.x=1/2 km^2

x=2F/k

x=2×50/100=1m