Question

A block of mass 1 kg is moving x axis .a force of 1 N acts on the block .the forceF always points toward the originO the magnitude of F is constant except at point O,where it is 0 at t=0 ,the block is released from rest at X=2 the period of motion of block is

Answer 1

Answer:

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Answer 2

Concept Introduction: Block movement is a part of Newton's law of Motion numericals.

Given:

We have been Given: mass of block

$1kg$

Force

$1 \: n$

$x = 2 \: sec$

To Find:

We have to Find: The period of motion of block.

Solution:

According to the problem, acceleration is

$a = 1m {s}^{ - 2}$

therefore,

$v = at = 1 \times 2 = 2m {s}^{ - 1}$

therefore total period of motion will be

$2 + 2 + 2 + 2 = 8sec$

Final Answer: The period of motion is

$8 \: sec$

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