A block of mass 1 kg is placed on the surface mu = 0.6 on a truck moving with acc 5m/s the froctional gorce
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.Frictional force=mu x mg
=0.6 x 1 x10
=6N
=0.6 x 1 x10
=6N
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Limiting friction, f = μmg = 0.6 × 1 × 9.8 = 5.88 N
Applied force = F = ma = 1 × 5 = 5 N
As F < f, so force of friction = 5 N
Applied force = F = ma = 1 × 5 = 5 N
As F < f, so force of friction = 5 N
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