Question

A block of mass 1 kg moves along x axis with variable velocity v=3t^2(m/s) .find the net work done on the block from t=1s to t=2s

Answer 1

Answer:

18 J

Explanation:

I've written this answer for you with a view that you know differential calculus.

m = 1 kg

v = 3t^2 m/s

t = (2-1) s = 1 s

Hence, a = dv/dt = d/dt (3t^2) = 6t.

Hence, the acceleration on the block is 6t.

F = ma = 1 * 6t = 6t.

s = ut + (at^2)/2 = 6t^3/2 = 3t^3.

W = F . s = 6t . 3t^3 = 18.

Hence, W = 18 J.

Hope this helps you!!

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Answer 2

67.5 is the answer...........