Physics, asked by jawaidsaman7281, 1 year ago

A block of mass 10 kg is kept on a fixed rough inclined plane of angle of inclination 30 degree

Answers

Answered by reetavyadav
9

When a

block of 10 kg is moving on a rough surface and the angle of inclination is 30,

the force of static friction is 5 kg.wt




1 kg.wt

means a force that is required to accelerate a mass of 1 kg with an

acceleration of approximately 9.8 m/s2


here the

friction force required to stop the block is mg*sin30


since

mass is equal to 10 kg


force

required = 10*g*sin30 newton


                       = 5*g newton


                       = 5 kg.wt      (since 1 kg.wt = 1*g newton, where g =

9.8 m/s2)


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