A block of mass 10 kg is kept on a fixed rough inclined plane of angle of inclination 30 degree
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When a
block of 10 kg is moving on a rough surface and the angle of inclination is 30,
the force of static friction is 5 kg.wt
1 kg.wt
means a force that is required to accelerate a mass of 1 kg with an
acceleration of approximately 9.8 m/s2
here the
friction force required to stop the block is mg*sin30
since
mass is equal to 10 kg
force
required = 10*g*sin30 newton
= 5*g newton
= 5 kg.wt (since 1 kg.wt = 1*g newton, where g =
9.8 m/s2)
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