Question

a block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction of 0.5 the minimum force required to move the block is​

Answer 1

Answer:

50 newtons

Explanation:

The mass of the block is 10 kilogrammes

To get the force required to move the block the formula is the weight of the block × The coefficient of friction

To get weight we take the mass multiply by the gravitational acceleration

The gravitational acceleration is usually 10 newtons therefore

10  × 10 = 100 newtons

We then proceed to applying the formula

100 × 0.5 = 50 newtons

The force required to move the block is 50 newtons.

Answer 2

Answer:

the mimimum force is required to move the block is 20 under root 5