Physics, asked by nanisaiprasad1234, 1 year ago

The resultant vector of ŌA = 2i +3j +6k and
OB=2i - 5j+3k is
(1) 4i+9k (2) 4i +8j+3K
(3) -2j+3k (4) 4i-2j +9k​

Answers

Answered by awaisanwar492
11

Answer:

AB =  4i - 2j + 9k

Explanation:

AB = OA + OB

AB = ( 2i +3j +6k ) + (  2i - 5j+3k )

AB =  2i + 2i+3j - 5j+ 6k + 3k

AB =  4i - 2j + 9k

Answered by vinod04jangid
1

Answer:

AB =  4i - 2j + 9k

Explanation:

Given:  ŌA = 2i +3j +6k, OB=2i - 5j+3k

To find: The resultant vector

AB = OA + OB

AB = ( 2i +3j +6k ) + (  2i - 5j+3k )

AB =  2i + 2i+3j - 5j+ 6k + 3k

AB =  4i - 2j + 9k

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