Question

A block of mass 10 kg is placed on a rough horizontal

surface having coefficient of friction = 0.5. If a

horizontal force of 100 n is acting on it, then

acceleration of the block will be

Answer 1

Answer:

you're answer !

Explanation:

Given

Mass (M) = 10kg

Co-efficient of friction (K) = 0.5

Horizontal force = 100 N

g = 10m/s2

Solution

Normal reaction = M * g = 10 * 10

Normal reaction = 100N

Friction force (F) = K * 0.5 = 0.5 * 100 = 50N

F = Ma

50 = 10 * a

a = 5 m/s2

a = 5 m/s2 is the direction of force

follow me !

Answer 2

Answer:

frictional force = 0.5 × 10 × 10 = 50 N

therefore the total force acting on the block will be = 100 + (-50) = 50N

(negative sign means opposite in direction)

now,

force = mass × acceleration

therefore,

Acceleration= 50N / 10kg

= 5 m/s^2.

Explanation:

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