A body is moving with uniform velocity of 2 m s1 on a rough level surface. The frictional force on it is 10 n. If the body moves with velocity 4 m s1 the force of friction will be:
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Explanation:
Hey dear,
◆ Answer-
F2 = 20 N
◆ Explanation-
# Given-
v1 = 2 m/s
v2 = 4 m/s
F1 = 10 N
# Solution-
As we know, frictional force depends on the velocity of the moving object.
i.e. F ∝ v
Thus, here-
F1/v1 = F2/v2
F2 = F1 × v2 / v1
F2 = 10 × 4 / 2
F2 = 20 N
Therefore, frictional force is 20 N.
Hope it helps...
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Secondary School Physics 5 points
A body is moving with uniform velocity of 2 m s1 on a rough level surface. The frictional force on it is 10 N. If the body moves with velocity 4 m s1 the force of friction will be: (a) 2.5 N (b) 5 N (c) 10 N (d) 20 N
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gadakhsanket
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Hey dear,
◆ Answer-
F2 = 20 N
◆ Explanation-
# Given-
v1 = 2 m/s
v2 = 4 m/s
F1 = 10 N
# Solution-
As we know, frictional force depends on the velocity of the moving object.
i.e. F ∝ v
Thus, here-
F1/v1 = F2/v2
F2 = F1 × v2 / v1
F2 = 10 × 4 / 2
F2 = 20 N
Therefore, frictional force is 20 N.
Hope it helps...