Question

A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction 0.5 how much acceleration in the block will be force of 100 N is applied

Answer 1

Given :-

A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction 0.5.

• Mass, m = 10 kg
• Coefficient of friction, μ = 0.5
• Acceleration due to gravity, g = 10 m/s²

To Find :-

The acceleration in the block when force of 100 N is applied.

→ F = 100 N

Solution :-

We know,

$\sf{f=\mu N}$

$\sf{\longrightarrow f=\mu mg}$

$\sf{\longrightarrow f=0.5\times10\times10}$

$\sf{\longrightarrow f=50\ N}$

____________________

Now, acceleration producing force, F₁ = F - f

$\sf{\longrightarrow F'=100-50}$

$\sf{\longrightarrow F'=50\ N}$

____________________

$\sf{\longrightarrow a=\dfrac{F'}{m}}$

$\sf{\longrightarrow a=\dfrac{50}{10}}$

$\sf{\longrightarrow a=5\ m/s^2}$

Therefore, the acceleration of the block when 100 N of force is applied, is 5 m/s².

Answer 2

$\huge\underline\bold{AnSwEr,}$

Given :-

A block of mass 10 kg is placed on a rough horizontal surface having coefficient of friction 0.5.

Mass, m = 10 kg

Coefficient of friction, μ = 0.5

Acceleration due to gravity, g = 10 m/s²

To Find :-

The acceleration in the block when force of 100 N is applied.

→ F = 100 N

Solution :-

We know,

$\sf{f=\mu N}$

$\sf{\longrightarrow f=\mu mg}$

$\sf{\longrightarrow f=0.5\times10\times10}$

$\sf{\longrightarrow f=50\ N}$

____________________

Now, acceleration producing force, F₁ = F - f

$\sf{\longrightarrow F'=100-50}$

$\sf{\longrightarrow F'=50\ N}$

____________________

$\sf{\longrightarrow a=\dfrac{F'}{m}}$

$\sf{\longrightarrow a=\dfrac{50}{10}}$

$\sf{\longrightarrow a=5\ m/s^2}$

Therefore, the acceleration of the block when 100 N of force is applied, is 5 m/s².

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