a block of mass 10 Kg is placed on rough horizontal surface the coefficient of friction is equals to 0.5 if a horizontal force of hundred Newton acting on it then find the acceleration(g= 10 10 metre per second square)
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Given
Mass (M) = 10kg
Co-efficient of friction (K) = 0.5
Horizontal force = 100 N
g = 10m/s2
Solution
Normal reaction = M * g = 10 * 10
Normal reaction = 100N
Friction force (F) = K * 0.5 = 0.5 * 100 = 50N
F = Ma
50 = 10 * a
a = 5 m/s2
a = 5 m/s2 is the direction of force...
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