A block of mass 10 kg is released on a fixed wedge Take initial velocity of block zero. Then find the work done by normal reaction (with respect to ground )on block in two second.
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Answer:
N=mg cosθ=4mg/5
Displacement along the wedge for two seconds = 0m
horizontal displacement of cart = 20m
Normal reaction = 4mg/5=80N perpendicular to wedge.
Work done by N = N.(s
1
+s
2
)
N×s
1
=80×20×sinθ=960
N×s
2
=0
W
N
=960J
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