Physics, asked by vaibhavpandey1, 1 year ago

a block of mass 10kg is moving on inclined pane with constant velocity 10m/s.The coefficient of kinetic friction between incline plane and block is.

Answers

Answered by abhi178
87
A block of mass 10kg is moving on inclined plane with constant velocity . means body doesn't move with acceleration. hence body is in inertial frame. so, we have to treat as equilibrium condition.

Let angle of inclination of plane is \theta
so, component of weight along plane = mgsin\theta
component of weight perpendicular to plane = mgcos\theta

at equilibrium,
components of weight along plane = friction
mgsin\theta = \muN
where \mu is coefficient of friction and N is normal reaction e.g., N = mgcos\theta

so, mgsin\theta=\mu mgcos\theta
\mu=tan\theta

hence, coefficient of friction = tan\theta
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Answered by ganeshank1997
4

Answer:

0.75

Explanation:

you have learn value of tan37

hope it will help

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