a block of mass 10kg is moving on inclined pane with constant velocity 10m/s.The coefficient of kinetic friction between incline plane and block is.
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Answered by
87
A block of mass 10kg is moving on inclined plane with constant velocity . means body doesn't move with acceleration. hence body is in inertial frame. so, we have to treat as equilibrium condition.
Let angle of inclination of plane is
so, component of weight along plane = mgsin
component of weight perpendicular to plane = mgcos
at equilibrium,
components of weight along plane = friction
mgsin = N
where is coefficient of friction and N is normal reaction e.g., N = mgcos
so, mgsin
hence, coefficient of friction = tan
Let angle of inclination of plane is
so, component of weight along plane = mgsin
component of weight perpendicular to plane = mgcos
at equilibrium,
components of weight along plane = friction
mgsin = N
where is coefficient of friction and N is normal reaction e.g., N = mgcos
so, mgsin
hence, coefficient of friction = tan
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Answered by
4
Answer:
0.75
Explanation:
you have learn value of tan37
hope it will help
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