A block of mass 10kg is pushed by a force F on a horizontal rough plane is moving with acceleration 5 ms-2 When force is doubled, its acceleration becomes 18ms-2. Find the coefficient of friction between the block and rough horizontal plane. (g = 10m/s2).
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Answer:
We know:
ma=F−μmg
Case 1:
5×10=F−100μ
Case 2:
18×10=2F−100μ
Solving simultaneously we get:
F=130N, μ=0.8
Answered by
0
Answer:
We know:
ma=F−μmg
Case 1:
5×10=F−100μ
Case 2:
18×10=2F−100
EXPLANATION
Solving simultaneously we get:
F=130N, μ=0.8
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