a block of mass 120 gram moves with a speed of 6.0 metre per second on a frictionless horizontal surface towards another block of mass 180 gram kept at rest they collide and the first block stops find the speed of the Other block after the collision
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let the speed of other block be X
Since, momentum before collision = momentum after collision
=120/1000*6 + 180/1000*0 = 120/1000*0 + 180/1000 X
= 48/100 + 0 = 0 + 18/100 X
= 18/100 X = 48/100
= X = 48/100*100/18
So, X = 9/24
яєgαя∂ѕ.......
ι нσρє уσυ нєℓρ !!!
let the speed of other block be X
Since, momentum before collision = momentum after collision
=120/1000*6 + 180/1000*0 = 120/1000*0 + 180/1000 X
= 48/100 + 0 = 0 + 18/100 X
= 18/100 X = 48/100
= X = 48/100*100/18
So, X = 9/24
яєgαя∂ѕ.......
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