Math, asked by lakshiyamanalan, 1 year ago

find the area and perimeter of the rectangle whose length is 15 cm and the length of one of its diagonals is 17cm ​

Answers

Answered by faisallife92
2

Answer:


Step-by-step explanation:

Length=15cm


L^2 + B^2= H^2

15^2 + B^2 = 17^2

B^2 = 289-225 = 64

B = 8


area of rectangle = Length×Breath

=15×8

= 120

perimeter of rectangle =

2 (Length + Breath) =

2 (15+8)

= 2 (23) = 46

Answered by PrahladRaoKulkarni
4
Using Pythagorean theorem in triangle ABC we will get the value of breadth of the rectangle. Using the formula of area of rectangle i.e( l×b) we will get the answer.


Perimeter = 2(l+b)
= 2(15+8)
= 2(23)
P = 46cm
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