find the area and perimeter of the rectangle whose length is 15 cm and the length of one of its diagonals is 17cm
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Answered by
2
Answer:
Step-by-step explanation:
Length=15cm
L^2 + B^2= H^2
15^2 + B^2 = 17^2
B^2 = 289-225 = 64
B = 8
area of rectangle = Length×Breath
=15×8
= 120
perimeter of rectangle =
2 (Length + Breath) =
2 (15+8)
= 2 (23) = 46
Answered by
4
Using Pythagorean theorem in triangle ABC we will get the value of breadth of the rectangle. Using the formula of area of rectangle i.e( l×b) we will get the answer.
Perimeter = 2(l+b)
= 2(15+8)
= 2(23)
P = 46cm
Perimeter = 2(l+b)
= 2(15+8)
= 2(23)
P = 46cm
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