Question

A block of mass 1kg is placed on turntable rotating
with constant angular velocity w about O. The
coefficient of friction between turntable and the
block is 0.4. The length of the string is 1m.
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Answer 1

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Here, the table is a circular table and so the frictional force is equivalent to the centripetal force of the table as it moving with a constant angular velocity.

A centripetal force is a force that makes a body follow a curved path. Its direction is always orthogonal to the velocity of the body and towards the fixed point of the instantaneous center of curvature of the path.

The equation for centripetal force using angular velocity is:

F =mω^2R

where, m = mass, ω = angular velocity, and R = radius of path of motion.

Hence, the friction force between block and table is mω^2R.

Answer 2

Answer:

anwer is m w^2 R.........