Question

A block of mass 1kg sliding on a smooth horizontal surface with a speed of 2ms^-1meet the free end of a long horizontal spring fixed at the other end having a spring constant 0.25Nm^-1. Find the meximum compression of the spring to bring the block of mass momentarily at rest.​

Answer 1

Answer:

Here we can use conservation of energy since no external agencies are acting.

K.E = Elastic potential energy

1/2mv^2 = 1/2kx^2

1kg × 4 = 0.25 × x^2

16 = x^2

Thus x = 4m compression

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