Question

A block of mass 2:0 kg is pushed down an inclined plane
of inclination 37° with a force of 20 N acting parallel to
the incline. It is found that the block moves on the
incline with an acceleration of 10 m/s?. If the block starts from rest, find the work done (a) by the applied force incrhe first second (b) by the weight of the block in the first second and (c) by the frictional force acting on the block in the first second.

Answer 1

Answer:

Work done by applied force is 100 J

Work done by the weight of block is 60 J

Work done by the friction force is -60 J

Explanation:

As we know that block is sliding on the rough inclined plane

So the force equation is given along the direction of motion as

$F = F_g sin37 + F - F_f$

$ma = mg sin37 + F - F_f$

$2(10) = 2(10)sin37 + 20 -F_f$

$F_f = 20(0.6) = 12 N$

distance moved by the block along the inclined plane is given as

$d = \frac{1}{2}at^2$

$d = \frac{1}{2}(10)(1^2)$

$d = 5 m$

a) Work done by the applied force

$W = F .d$

$W = 20 (5) = 100 J$

b) Work done by the weight of the block

$W = mg sin37 . d$

$W = 2(10) sin37 (5)$

$W = 60 J$

c) Work done by friction force

$W = - F_f d$

$W = -12 (5)$

$W = -60 J$

#Learn

Topic : Work

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