Question

A block of mass 2 kg hangs in equilibrium with the help of two strings OP and OQ as shown in figure. The tension in the strings T, and I are respectively

Answer 1

Answer:

Various forces acting on the ball are as shown in figure. The three concurrent forces are in equilibrium. Using Lami's theorem,

sin150

∘

T

1

​

​

=

sin120

∘

T

2

​

​

=

sin90

∘

10

​

or  

sin30

∘

T

1

​

​

=

sin60

∘

T

2

​

​

=

1

10

​

∴T

1

​

=10sin30

∘

=10×0.5=0.5N

and T

2

​

=10sin60

∘

=10×

2

3

​

​

=5

3

​

N

Explanation:

Answer 2

Answer:

Two strings, OP and OQ, are used to support an equilibrium between a block having a mass of 2 kg. The values of the $T_{1}$ and $T_{2}$ are, respectively, $T_1$ and $T_2$ are $=0.5 \mathrm{~N}$ and $=5 \sqrt{3} \mathrm{~N}$

Explanation:

What do you meant by tension in the string ?

As said, the block is being acted upon by many factors. Equilibrium exists between the three opposing forces. By means of Lami's theorem,

$\begin{aligned}& \frac{T_1}{\sin 150^{\circ}}=\frac{T_2}{\sin 120^{\circ}}=\frac{10}{\sin 90^{\circ}} \\& \text { or } \frac{T_1}{\sin 30^{\circ}}=\frac{T_2}{\sin 60^{\circ}}=\frac{10}{1} \\& \therefore T_1=10 \sin 30^{\circ}=10 \times 0.5=0.5 \mathrm{~N} \\& \text { and } T_2=10 \sin 60^{\circ}=10 \times \frac{\sqrt{3}}{2} \\& =5 \sqrt{3} \mathrm{~N}\end{aligned}$

The string's tension is$T _{1} =19.62 \mathrm{~N} . T _{2} =5 \mathrm{~kg}$ to calculate the tension. $T _{1} =19.62 \mathrm{~N} . T _{2} =5 \mathrm{~kg}$.

When a body is suspended from materials like chains, cables, and strings, tension acts as a drawing force on the body. T stands in for it (occasionally also symbolised as Ft). As stated in the tension formula. The period of oscillation, generally referred to as simply "period," is denoted by the letter "T" in the formula T=mg+ma.

To learn more about string tension refer to :

https://brainly.in/question/15615584

https://brainly.in/question/47888314

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