A block of mass 2 kg, initially moving with velocity of 8 m/s on frictionless surface, collides with another block
of mass 2 kg resting on the edge of the surface having value of kinetic friction as 4 N. After collision the two
blocks stick and move together. Find the distance travelled by both the blocks before they come to rest.
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Explanation:
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The FBD will be as
For equilibrium in vertical direction
N−mg=0
N=mg=(2)10=20 N
The normal contact force applied by the surface is 20 N, thus by Newton's third law of motion, 20 N force will be exerted by the block on the surface.
Option A is correct.
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